Alkaline Performs “Formula” On Fox 5 In New York

Alkaline recently made his first television performance in the United States following his appearance on Fox 5 in New York.

The Dancehall deejay performed his 2016 hit single “Formula” for millions of viewers via the mainstream TV network on August 10.

Watch Alkaline’s performing “Formula” on Fox 5 NY.

Alkaline has been in the United States for the past few weeks. He recently performed at a number of events including the Six Flags Caribbean Concert in New York.

The “Fleek” deejay has returned to the forefront of the Dancehall scene after a noticeable hiatus by releasing several hit singles including “Perfect,” “Pick Unnu Side,” and summer-flavored “Yardie Fiesta.”